There is hardly any theory which is more elementary than linear algebra, in spite of the fact that generations of professors and textbook writers have obscured its simplicity by preposterous calculations with matrices. - Jean Dieudonné (1906-1992)
Linear algebra is required knowledge for any technical discipline: Computer science, Physics, Electrical engineering, Mechanical engineering, Statistics etc. - although it is poorly understood by students.
We probably would have learned so many (crazy) things like,
\[ A \times B= \begin{bmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \\ \end{bmatrix} \begin{bmatrix} b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23} \\ b_{31} & b_{32} & b_{33} \\ \end{bmatrix}= \]
\[ \begin{bmatrix} a_{11}b_{11}+a_{11}b_{21}+a_{11}b_{31} & a_{12}b_{12}+a_{12}b_{22}+a_{12}b_{32} & a_{13}b_{13}+a_{13}b_{23}+a_{12}b_{33} \\ a_{21}b_{11}+a_{21}b_{21}+a_{21}b_{31} & a_{22}b_{12}+a_{22}b_{22}+a_{22}b_{32} & a_{23}b_{13}+a_{23}b_{23}+a_{23}b_{33} \\ a_{31}b_{11}+a_{31}b_{21}+a_{31}b_{31} & a_{32}b_{12}+a_{32}b_{22}+a_{32}b_{32} & a_{33}b_{13}+a_{33}b_{23}+a_{33}b_{33} \\ \end{bmatrix} \]
or formula for computing determinants:
\[ det(A)= \begin{vmatrix} a_{11} & a_{12} \\ a_{21} & a_{22}\\ \end{vmatrix} = a_{11}a_{22}-a_{12}a_{21} \]
or cross products,
\[ v \times u= det\begin{vmatrix} \hat{i} & \hat{j} & \hat{k}\\ v_{1} & v_{2} & v_{3} \\ u_{1} & u_{2} & u_{3} \end{vmatrix} \]
or eigenvalues,
\[ det(A-\lambda I) = 0\]
But they might really come out without understanding why they are defined the way they are.
We are vaguely aware of the geometric intuition behind such definitions.
Numeric and geometric understanding differ fundementally. While numeric understanding allows us to do actual computations, geometric understanding is helpful for:
Without geometric understaning, professors teaching applications look like wizzards and linear algebra looks intimidating!
For example, if you are taught from your young age that sin
function is:
\[ sin(x) = x-\frac{x^3}{3!}+\frac{x^5}{5!}+\dots+(-1)^{n}\frac{x^{2n+1}}{(2n+1)!}+\dots\] and vaguely know it is related to triangles.
If you are sitting in a physics class learning trajectories:
\(\|v\| sin\theta\) for the force acting downwards would seem magical.
Luckily, linear algebra is not too different!
There are visual intuitions underlying the subject.
And unlike the above sin
example, the visual intuitions are much straight forward and lot of what it has been taught in a numeric way will sound more reasonable.
In fairness, many professors will make an attempt to convey the geometric understanding, but lots of courses spend disproportinate amount of time in numerical side of things, especially in this day and age where numerical computations can be left to computers and we focussing on conceptual ideas.
In the following sections, we will try to understand the basics of linear algebra through geometric intuition.
The introduction of numbers as coordinates is an act of violence - Hermann Weyl
Vectors are seen differently by different folks.
Physics student perspective: Magnitude and direction. Coordinate free. Eg., force.
CS student perspective: Ordered lists of numbers. Model using array of numbers where order matters. In R programming it is essentially a list with same data type.
Math student perspective: Tries to generalize both these views. A vector can be anything as long as we can add two vectors or multiply a vector with a scalar.
The later view comes from the fact that addition and scalar multiplication is extremely useful throughout linear algebra.
In math, we always think a vector is rooted in some origin. In two dimensions, every pair of numbers is associated with only one vector and every vector is associated with only one pair of numbers.
Vector addition is an extension of 1-d addition.
In general,
\[ \begin{bmatrix} x_1 \\ y_1 \\ \end{bmatrix} + \begin{bmatrix} x_2 \\ y_2 \\ \end{bmatrix} = \begin{bmatrix} x_1+x_2 \\ y_1+y_2 \\ \end{bmatrix} \]
Scaling a vector by a constant expands or squishes it by the factor it is scaled,
At the end of the day, it doesn’t matter if you think vectors as fundamentally arrows in space (physcists view) with numbers associated to them or lists of numbers (computer scientists view) with arrows associated with them, the usefullness of linear algebra lies in the fact that these notions are interchangeable.
This gives data scientits to conceptualize numbers in a visual way (like PCA) that identifies patterns in data and gives a global view of what certain operations do.
On the other hand it gives physicists and graphics programmers a language to describe and manipulate space that can be crunched and run in a computer.
Vector space (Technical Definition): A space containing vectors where any two vectors can be added and any vector can be multipled by scalars, to produce another vector.
Mathematics requires a small dose, not of genius, but of an imaginative freedom which, in a larger dose, would be insanity. - Angus K. Rodgers
In two dimensions, there are two special vectors, \(\hat{i}\), one that points in the \(x\)-direction and \(\hat{j}\), the one that points in the \(y\)-direction. Then each coordinate can be imagined as scalers.
One can think of:
\(\hat{i}\) and \(\hat{j}\) have a special name - basis vectors of the \(xy\)- coordinate system. What if we choose different basis vectors?
Then the values of the coordinates will change depening on this change in the basis vectors.
Thus, anytime, you define a vector using numbers, the coordinates implicitly depend on the basis vectors.
Terminology: If \(\vec{u}\) and \(\vec{v}\) are two vectors and \(a\) and \(b\) are scalars, the sum \(a\vec{u}+b\vec{v}\) is called the linear combination of the vectors.
Why is the name called linear combination? What is so “liny” about them?
Fix one of the scalars and allow the value to roam freely, we get a line.
Terminology: If you allow both \(a\) and \(b\) freely, the resulting sum is called the span of the vectors \(\vec{u}\) and \(\vec{v}\).
Three things can happen in two-dimensions:
Question: What is the span of two vectors in 3-d space?
How about if we add one more vector? If the third vector is in the same plane - we are trapped!!
Another way of saying this is the vectors are linearly dependent.
Otherwise, the plane will move (think of continously varying the third vector) and the vectors are referred as linearly independent.
Basis (Technical Definition): The basis of a vector space is a set of linerly independent vectors that span the entire space.
Why this definition makes sense?
Unfortunately no one can be told what the Matrix is. You have to see it for yourself. - Morpheus
As the name suggests, transformation essentially means a function - takes an input vector and spits another vector. Arbitrary transformations like this are not linear.
The key word is linear. All lines should remain lines and the origin should be fixed. Thus, this is not a linear transformation.
And not this as well (since origin moves)…
How about this?
Note: This keeps lines as lines and the origin fixed.
In general, one can think of linear transformation as some function that keeps grid lines parallel and evenly spaced.
Some are simple to think about - like rotation for instance,
How do we describe these transformations numerically? That is,
\[ \begin{bmatrix} x_{in} \\ y_{in} \\ \end{bmatrix} \Rightarrow \text{???} \Rightarrow \begin{bmatrix} x_{out} \\ y_{out} \\ \end{bmatrix} \]
It turns out we need to only find out where the unit vectors \(\hat{i}\) and \(\hat{j}\) land. Everything will follow from that. As an example:
Thus for any arbitrary vectors \([x,y]^T\), we have:
All this says is a two-dimensional linear transformation is described by just two sets of numbers.
The two coordinates where \(\hat{i}\) lands and two coordinates where \(\hat{j}\) lands.
It is elegent to package these two sets of numbers in a \(2 \times 2\) grid of numbers, called a matrix and often written like this:
\[ M= \begin{bmatrix} 1 & 3 \\ -2 & 0 \\ \end{bmatrix} \]
If you want to know where an arbitray point, say,
\[ P = \begin{bmatrix} x \\ y \\ \end{bmatrix} \]
goes, just multiply the first number by where \(\hat{i}\) lands and the second number by where \(\hat{j}\) lands. That is,
\[ P = x\begin{bmatrix} 1 \\ -2 \\ \end{bmatrix} + y\begin{bmatrix} 3 \\ 0 \\ \end{bmatrix} \]
Therefore, in general, we can think of a matrix vector multiplication,
\[\begin{bmatrix} a & b \\ c & d \\ \end{bmatrix} \begin{bmatrix} x \\ y \\ \end{bmatrix} = x \begin{bmatrix} a \\ c \\ \end{bmatrix}+ y \begin{bmatrix} b \\ d \\ \end{bmatrix} = \begin{bmatrix} ax + by \\ cx + dy \\ \end{bmatrix} \]
as just a transformation of points.
Rotation:
Sheer (\(\hat{i}\) remains the same, while \(\hat{j}\) moves to \([1,1]^T\)):
If the columns are linearly dependent, that is if one column is a multiple of another, the whole line squishes:
To sum up:
Linear transformations are a way to move around space such that grid lines remain parallel and evenly spaced. The origin goes to origin.
Delightfully, these transformations can be described only through a handful of numbers, the coordinates of where each basis vectors lands.
Matrices gives us a language to describe these transformations where columns represents those coordinates
And matrix vector multiplication shows what that transformation does to a given vector.
Everytime you see a matrix, you can interpret it as a certain transformation of space.
This is a very critical idea to understand linear algebra.
Linear transformation (Technical Definition): A mapping \(L\) from a vector space \(V\) to another vector space \(W\), is called a linear transformation, if for any two vectors \(u,v \in V\) and a scalar \(c\), we have, \[ L(u+cv) = L(u)+cL(v) \]
It is my experience that proofs involving matrices can be shortened by 50% if one throws the matrices out. - Emil Artin
Often times we may want to describe what happens when we apply one transformation and then another.
For example, a rotation plus shearing. Note that the resulting final transformation is also linear becuase evenly spaced and parallel grids will remain the same, the origin being fixed.
Equivalently,
The new transformation is commonly called the composition of transformations.
The new matrix is supped to capture the over all effect of sheering and rotating.
Let us compute the composition of two matrices \(M_1\) and \(M_2\).
In general, we can see,
Really it just represents applying one transformation after another.
Note that it matters if we apply sheer or rotation first, and the other, next.
In general, rotation & sheer \(\neq\) sheer & rotation. That is why matrix multiplication is non-commutative. \(M_1M_2 \neq M_2M_1\).
Associativity, \(M_1(M_2M_3) = (M_1M_2)M_3\), is trivial if we think about applying transformations sequentially. Notoriously painful to think in terms of matrices.
Also, all these ideas apply to three and higher dimensions.
The purpose of computation is insight, not numbers. - Richard Hamming
Some transformations stretch the space while others squish it. It will be good to know how much does a trasformation stretches or squishes the space. Area is a good measure.
For example consider the transformation,
The new area is \(3 \times 2 = 6\).
Whereas for a sheer like this,
the area remains fixed.
Even though this sheer transformation seems to squish things around, the area remains the same, at least in the case of 1 unit square.
In fact, if we know how one unit square changes, we can know how any area changes, because linear transformations leave grid lines parallel and evenly spaced.
This special scaling factor, the factor by which the linear transformation changes any area is called the determinant of that transformation.
For example, the determinant of a transformation is \(3\) if it increases the area after transformation, by \(3\).
The determinant of a 2D transformation is zero of it squshes all the plane into a single line.
This is a pretty important concept because it will allow us to determine if the transformation reduces our points into a smaller dimenstions.
Note: Whatever we said about determinants is when determinant is a positive quantity.
What does a negative determinant even mean?
It has to do with the idea of orientation. Any tranformation that flips the axes is said to invert the orientation of space.
After transformation if the axes direction are reversed:
the determinant of such transformations will be negative.
The absolute value will still tell us by which factor the area is scaled.
Another way to think about this is as follows:
The idea of determinants representing area extends to three dimensions.
In this case we will have parallelopiped instead of parallelogram’s.
A volume of zero means the entire parallelopiped gets squished into zero volume, meaning the vectors would either lie on a plane, or a line or become a single point.
This means the columns of the matrix are linearly dependent (i.e, one is a multiple of the other).
What does negative determinant mean in 3-dimensions? Right hand and left hand rule:
How do we compute determinants?
To ask the right question is harder than to answer it. - Georg Cantor
Several real world applications come in the form of linear equations.
Even in the case of non-linear equations, they can be approximated by linear equations to a good degree.
Linear algebra is very useful in solving such equations.
Here is how we think about matrices:
In general, the solution of this would depend on how \(A\) behaves - whether it squishes all points to a line (or a point) or not.
Thus, \(det(A)\) would determine the solution(s).
For every transformation \(A\), where \(det(A) \neq 0\), we can apply the inverse of the transformation.
Thus, for instance, if we rotate by \(90^{\circ}\) clockwise, we can rotate by \(-90^{\circ}\) anti-clock wise.
The result of such inverse transformation (if it exists) applied to a transformation should leave the vectors intact.
That is, \([A^{-1}A]x=x\), for any vector \(x\).
When \(det(A)=0\), the space is squished into smaller dimensions, there is no inverse.
We cannot unsquish a line to make a plane.
The same happens in three dimensions and there is a name for different types of zero determinant cases.
The name is rank of a matrix.
If the output of a transformation is a line, we say it has rank \(1\)
In three dimensions, if the output is a plane, the rank is \(2\)
The word rank means the number of dimensions in the output.
The set of all outputs for a transformation is called the column space of a transformation.
It is the span of the columns.
If the span equals the full space we call the transformation has full rank.
Note The zero vector is always included in the column space since linear transformations must keep the origin fixed in place.
For any non-full rank transformation there could be an entire range of vectors that gets squshed to orgin.
In 2D, if a transformation squishes to a line, there is a bunch of vectors that gets squished to the origin.
In 3D, if a transformation squishes to a plane, there is a bunch of vectors that gets squished to the origin.
In 3D, if a transformation squishes to a line, there is entire plane that gets squished to the origin.
The set of such vectors that gets squished to the origin, for any transformation, is called the null space or kernel of the transformation.
In a sense, it a set of vectors that “becomes null”.
On this quiz, I asked you to find the determinant of a \(2 \times 3\) matrix. Some of you, to my great ammusement, actually tried to do this. - via mathprofessorquotes.com (no name listed)
We can think of transformations between dimensions:
All we need is grid-lines should remain parallel and evenly spaced and origin should map to origin. We have the same interpretation of the coordinate transformation, namely, where \(\hat{i}\) and \(\hat{j}\) lands.
In the language of the last few slides, this matrix has a full rank since the number of dimensions of the column space is same as the number of dimensions of the input space, namely, \(2\).
Quiz: What does a \(2x3\) matrix mean?
A much better presentation:
Shamelessly reproduced from my favorite math explainer:
https://www.youtube.com/playlist?list=PLZHQObOWTQDPD3MizzM2xVFitgF8hE_ab
You should seriously watch his videos.